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What Is Torque? Formula and Real-World Examples

Physics Fundamentals Editorial TeamPhysics FundamentalsUpdated Jul 29, 202614 min read
Torque in physics — spanner turning a bolt illustrating rotational force and moment arm

You already apply torque correctly before you know what it is. You push a door near the edge, not near the hinge. You use a long wrench, not a short one, when a bolt is stuck. You know intuitively that the turning effect of a force depends on both the force magnitude and where it's applied. Torque formalises that intuition: τ = rF sinθ, where r is the distance from the pivot and θ is the angle between the force and the lever arm.

Torque is to rotation what force is to linear motion — the cause of angular acceleration. Every gear system, every engine crankshaft, every balanced beam, every joint in the human body involves torque. It's also the quantity that determines whether a structure is in rotational equilibrium, which is the foundation of statics and structural engineering.

Quick overview
  • The torque formula τ = rF sinθ — what each term means and how to apply it
  • The conditions for rotational equilibrium (Στ = 0) and how to use them
  • Torque and angular acceleration: τ = Iα and its analogy with F = ma
  • Worked examples including levers, beams, and rotating systems

The Formula of Torque

τ = Fd sinθ

where τ (tau) is torque (N·m), F is force (N), d is the distance from the axis of rotation to the point where the force is applied (m), and θ is the angle between the force vector and the line from pivot to point of application.

When the force is perpendicular to the moment arm (θ = 90°, sinθ = 1), torque is maximised:

τ = Fd (maximum, when F ⊥ moment arm)

When the force is parallel to the moment arm (θ = 0° or 180°, sinθ = 0), torque is zero — a force directed straight toward or away from the pivot produces no rotation.

The Moment Arm

The moment arm (also called the lever arm) is the perpendicular distance from the axis of rotation to the line of action of the force. It is not necessarily the distance from pivot to point of application — it is the shortest (perpendicular) distance from the pivot to the extended line along which the force acts.

For a force perpendicular to the lever: moment arm = distance from pivot to point of application.

For a force at angle θ: moment arm = d sinθ, so τ = F × (d sinθ) = Fd sinθ.

Diagram — Torque: force, moment arm, and angle

pivot d (moment arm) F θ F sinθ τ = Fd sinθ = F⊥ × d

Direction of Torque: Clockwise and Anticlockwise

Torque is a vector — it has both magnitude and direction. By convention:

Anticlockwise (counterclockwise) torques are positive.

Clockwise torques are negative.

The direction is determined by the right-hand rule: curl the fingers of the right hand from the moment arm toward the force direction; the thumb points in the direction of the torque vector (perpendicular to the plane of rotation).

Rotational Equilibrium: The Principle of Moments

An object is in rotational equilibrium when the net torque about any axis is zero:

Σ τ = 0 (sum of all torques = 0)

This is the Principle of Moments: for equilibrium, the sum of clockwise torques about any pivot equals the sum of anticlockwise torques. This is the fundamental principle behind levers, see-saws, balance scales, and structural engineering.

Worked Example: See-saw

A 40 kg child sits 1.5 m from the centre of a see-saw. How far must a 60 kg adult sit on the other side for the see-saw to balance?

τ_child = 40 × 9.8 × 1.5 = 588 N·m (anticlockwise)
τ_adult = 60 × 9.8 × d = 588 N·m → d = 588 / (60 × 9.8) = 1.0 m

The adult must sit 1.0 m from the centre — lighter people sit further from the pivot to balance heavier people sitting closer.

Worked Example: Beam on Two Supports

A uniform beam of length 4 m and weight 200 N rests horizontally on two supports: one at end A, and one 1 m from the other end (3 m from A). Find the reaction force at each support.

The beam's weight acts at its centre of mass, 2 m from A. Taking moments about support A eliminates the unknown reaction at A from the equation, leaving only the reaction at the second support:

R_B × 3 = W × 2 = 200 × 2 = 400 N·m
R_B = 400 / 3 = 133.3 N

Then using ΣF = 0 (total upward force equals the beam's weight):

R_A = W − R_B = 200 − 133.3 = 66.7 N

The support closer to the beam's centre of mass carries less of the load — this "choose the pivot at an unknown force" trick, used here to solve for R_B without ever needing R_A, is the standard technique for any beam problem with multiple unknown reactions.

More Worked Examples

Example 2: Tightening a bolt

A mechanic applies 80 N perpendicular to a 0.25 m spanner. What torque acts on the bolt?

τ = Fd = 80 × 0.25 = 20 N·m

Example 3: Force at an angle

A 100 N force acts at 35° to a 0.4 m moment arm.

τ = 100 × 0.4 × sin 35° = 40 × 0.574 = 22.9 N·m

Newton's Second Law for Rotation

Just as F = ma connects force and linear acceleration, the rotational equivalent connects torque and angular acceleration α:

τ_net = Iα

where I is the moment of inertia (kg·m²) — the rotational analogue of mass — and α is angular acceleration (rad/s²). A larger moment of inertia means the same torque produces less angular acceleration. This is why it is harder to spin a long, heavy flywheel than a small, light disc — even if both have the same mass, the flywheel's mass is concentrated further from the axis, giving it a greater moment of inertia.

Common Moments of Inertia

Moment of inertia depends on both mass and how that mass is distributed relative to the axis of rotation:

Shape (axis) Formula
Point mass, distance r from axisI = mr²
Rod, about the centreI = (1/12)mL²
Rod, about one endI = (1/3)mL²
Disc or cylinder, about centreI = (1/2)mr²
Solid sphere, about centreI = (2/5)mr²

Notice that a rod rotated about its end has three times the moment of inertia of the same rod rotated about its centre (1/3 vs 1/12) — mass distributed further from the axis contributes disproportionately more, since the formula depends on the square of the distance.

Worked Example 4: Angular Acceleration from Torque

A flywheel is modelled as a solid disc of mass 5 kg and radius 1 m. A net torque of 15 N·m is applied. Find its angular acceleration.

I = (1/2)mr² = 0.5 × 5 × 1² = 2.5 kg·m²
α = τ/I = 15 / 2.5 = 6 rad/s²

The flywheel's angular velocity increases by 6 radians per second, every second, for as long as the 15 N·m torque is applied — directly analogous to a = F/m in linear motion.

Torque and Work in Rotation

Work done by a torque through angle θ (in radians):

W = τθ

Power delivered by a torque at angular velocity ω (rad/s):

P = τω

This mirrors the linear relationships W = Fd and P = Fv exactly. For a car engine: engine torque × angular velocity = power output. High-revving engines (large ω) can produce high power at moderate torque; diesel engines produce high torque at low revs. Torque and power are related by P = τω — they are not independent quantities.

Real-World Applications of Torque

Door handles: positioned at the edge of the door (maximum moment arm) to minimise the force needed to open it. A handle near the hinge would require enormous force for the same torque.

Wheelie bars on dragsters: prevent the car from rotating (wheelie) by extending the effective wheelbase, increasing the anticlockwise torque of the rear downforce.

Torque wrenches: allow engineers to apply precisely specified torques to bolts, preventing both under-tightening (bolt works loose) and over-tightening (stripping threads or warping flanges).

Seesaws and levers: all governed by the principle of moments — the fundamental application of rotational equilibrium dating back to Archimedes, who reportedly said: "Give me a lever long enough and a fulcrum on which to place it, and I shall move the world."

Try it yourself: check your own numbers with the Torque Calculator, which shows the formula, the worked substitution and the answer step by step.

Frequently Asked Questions

What is the formula of torque?
The formula of torque is τ = Fd sinθ, where τ (tau) is torque in newton-metres (N·m), F is the applied force in newtons, d is the distance from the pivot to where the force is applied (the moment arm, in metres), and θ is the angle between the force vector and the moment arm. Torque is maximum (τ = Fd) when the force is applied perpendicular to the moment arm, and zero when the force acts along the same line as the moment arm.
What is torque in physics?
Torque is the rotational effect of a force — the tendency of a force to cause angular acceleration about a pivot point. It is calculated as τ = rF sin θ, where r is the distance from the pivot to the point of force application, F is the force magnitude, and θ is the angle between the force and the line from pivot to application point. Unit: N·m. Maximum torque is produced when force is perpendicular to the lever arm (θ = 90°); zero torque when the force acts along the lever arm or passes through the pivot.
What is the difference between torque and force?
Force (F, in newtons) causes linear acceleration: F = ma. Torque (τ, in N·m) causes angular acceleration: τ = Iα. Force acts at a point; torque depends on both force and its distance from the rotation axis (moment arm). The same force produces more torque when applied further from the pivot — why door handles are at the far edge of the door and why longer spanners give more torque. While force and torque have similar dimensions (both involve N·m when you expand), they are distinct quantities — work (also in N·m = joules) is force times displacement, whereas torque is force times perpendicular distance.
What is the unit of torque?
Newton-metres (N·m). Note: this is the same unit as the joule (J = N·m) but torque and energy are different physical quantities — torque is a vector, energy is a scalar. The units happen to be identical but the contexts are distinct: torque is force × distance (perpendicular), energy is force × displacement (parallel).
Why is torque maximum when the force is perpendicular to the moment arm?
τ = Fd sinθ. sinθ is maximum (= 1) when θ = 90° — when the force is perpendicular to the moment arm. At this angle, 100% of the force contributes to rotation. At other angles, only the perpendicular component (F sinθ) produces rotation; the parallel component acts through the pivot and creates no torque.
What is the moment arm (lever arm)?
The moment arm (or lever arm) is the perpendicular distance from the pivot point to the line of action of the force. Torque = force × moment arm = F × r⊥. This is equivalent to τ = rF sin θ, since r sin θ = r⊥ (the perpendicular component of r). The moment arm is always the shortest distance from the pivot to the line along which the force acts. Maximising the moment arm maximises torque for a given force — why you open a door by pushing at the edge (large r⊥) not near the hinges (small r⊥).
What are the conditions for rotational equilibrium?
For rotational equilibrium, the net torque about any point must be zero: Στ = 0. Combined with translational equilibrium (ΣF = 0), this ensures a body is in complete static equilibrium — no linear or angular acceleration. When choosing a pivot point for torque calculations, placing it at an unknown force eliminates that unknown from the torque equation (since its moment arm is zero). This is the standard approach for solving beam, bridge, and seesaw problems where multiple unknown reaction forces exist.
How does torque relate to power in rotating machines?
Power = torque × angular velocity: P = τω. For an engine producing torque τ at rotational speed ω (rad/s): P = τω. Converting to more familiar units: if torque is 200 N·m and the engine runs at 3,000 rpm = 3000 × 2π/60 = 314 rad/s, then P = 200 × 314 = 62,800 W = 62.8 kW = 84 hp. This relationship explains why electric motors (high torque at low speed) and petrol engines (lower torque but higher speed range) have different power characteristics, and why gearboxes trade torque for speed to match engine output to road conditions.

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Physics Fundamentals Editorial Team

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